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EQ1: `4x-y=5 ` EQ2: `4x+4y=-4`
Note that we may re-write EQ2 as:
Then, substitute this to EQ1.
Then, isolate y.
Substitute the value of y to 4x=-4-4y and solve for x.
`y=-9/5` , `4x=-4 -4(-9/5) = -4+36/5= 16/5`
`x=(16/5)/4 = 4/5`
Hence, the solution to the given system of equations is `x=4/5` and `y=-9/5` .
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