Solve limit using L'Hopital's rule: lim(2/pi arccos x)^(1/x), if x->0

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We can use that `lim_(x->0) f(x) = lim_(x->0) e^(ln(f(x))) = e^(lim_(x->0+)ln(f(x)))`

`lim_(x->0) (2/pi arccos(x))^(1/x) = lim_(x->0) e^(ln((2/pi arccos(x))^(1/x)))`


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