Solve the inequality 2x^2 + 4x >= 6
Solve `2x^2+4x>=6 ` :
`2(x^2+2x-3)>=0 ` Since 2>0 we look at the quadratic:
For x<-3, the left side is positive.
For -3<x<1 the left side is negative.
For x>1 the left side is positive.
(In each case, try a test value such as x=-4,x=0,x=2)
Thus the solution intervals are `x<=-3 ` or `x>=1 `
In interval notation the solution is `(-oo,-3]uu[1,oo) `
Excellent answer, embizze!