# Solve it graphically: X+3y=12 x^2+y^2=9Explain with steps please

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We notice that the line and the circle do not intersect.

Therefore, there are NO solution.

x + 3y = 12

This an equation of a line, then we will rewrite as a function of x.

==> y= (12-x)/3

Now when x = 12 ==> y= 0 ==> (12,0) is one point of the line.

==> when x = 0 ==> y= 4 ==> (0, 4) is another point of the line.

We dot both points and connect a line between the,

The graph shown below (black line)

x^2 + y^2 = 9

This equation is an equation of a circle whose center is (0, 0) and radius 3.

Then, we will draw a circle whose center in the origin point and passe through the point (3,0) , (-3,0), (0,-3) , and (0,3).

The graph is shown below as a red circle.