Solve: `sin^2x = cos^2x`
Take the square root of both sides.
`sin x = cos x`
Then, refer to Unit Cirle Chart to determine the angle that resulted to same values of sine and cosine function.
Base on it, the `theta` that makes the angle sine and cosine equal are `pi/4 , and (5pi)/4` .
Since there is no indicated interval for the value of the angle, the general solution is:
>> `theta_1 = pi/4 + 2pi k` and `theta_2 = (5pi)/4 + 2pi k` (Answer)
The equation `sin^2x = cos^2x` has to be solved.
`sin^2x = cos^2x`
=> `tan^2x = 1`
=> tan x = 1 and tan x = -1
=> x = `tan^-1(1)` and x = `tan^-1(-1)`
=> x = 45 degrees and x = -45
The general solution of the equation is 45 + n*180 and -45 + n*180 degrees.