Question

Solve the following simultaneous equations.
x + 3y = 2 , 2x + 8y = 6

Accepted Answer

We have to solve the following set of simultaneous equations:
x + 3y = 2 ...(1)
2x + 8y = 6 ...(2)
2*(1) - (2)
=> 2x + 6y - 2x - 8y = 4 - 6
=> -2y = -2
=> y = -2/-2
=> y = 1
substitute in (1)
x + 3 = 2
=> x = 2 - 3
=> x = -1
We get x = -1 and y = 1

Answer

x + 3y = 2 
x = 2 - 3y
plug it in as x into the other equation:
2(2 - 3y) + 8y = 6
4 - 6y + 8y = 6
bring like terms to the same side:
-6y + 8y = 6 - 4
combine:
2y = 2
divide by 2
y = 1x + 3(1) = 2 
x + 3 = 2
subtract 3
x = 2 - 3
x = -1(-1 , 1)

Answer

x + 3y = 2 
x = 2 - 3y
plug it in as x into the other equation:
2(2 - 3y) + 8y = 6
4 - 6y + 8y = 6
bring like terms to the same side:
-6y + 8y = 6 - 4
combine:
2y = 2
divide by 2
y = 1
now plug that into any of the problems:
x + 3(1) = 2 
x + 3 = 2
subtract 3
x = 2 - 3
x = -1
(-1 , 1)

Answer

We'll solve the system using substitution method and we'll write x from the 1st equation, with respect to y:
x = 2 - 3y
We'll substitute x in the 2nd equation:
2(2 - 3y) + 8y = 6
We'll remove the brackets:
4 - 6y + 8y = 6
We'll combine like terms:
2y = 6 - 4
2y = 2
y  = 1
We'll substitute y in the first equation:
x + 3 = 2
x = 2  - 3
x = -1
The solution of the system is represented by the pair (-1 ; 1).

algebra1

Solve the following simultaneous equations. x + 3y = 2 , 2x + 8y = 6

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