x - 2y = 6.............(1)
x + 2y = 8............(2)
We will solve using the elimination method.
We will add (1) + (2).
==> 2x = 14
Now we will divide bu 2.
==> x = 7
Now we will substitute into (1) to determine y.
==> x - 2y...
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x - 2y = 6.............(1)
x + 2y = 8............(2)
We will solve using the elimination method.
We will add (1) + (2).
==> 2x = 14
Now we will divide bu 2.
==> x = 7
Now we will substitute into (1) to determine y.
==> x - 2y = 6
===> 7 - 2y = 6
==> -2y = -1
==> y= 1/2
Then the answer is the pair ( 7, 1/2)
We have to solve the following set of simultaneous equations:
x - 2y = 6 ...(1)
x + 2y = 8 ...(2)
(2) - (1)
=> x + 2y - x + 2y = 8 - 6
=> 4y = 2
=> y = 2/4
=> y = 1/2
substitute in (1)
x - 2y = 6
=> x = 6 + 2y
=> x = 6 + 2*(1/2)
=> x = 6 + 1
=> x = 7
We get x = 7 and y = 1/2