Please restrict your questions to one question:

The ratio of sums of money in three bags A,B, and C is 4:3:2. If $50 is added to each of the bags, the ratio becomes 14:13:12.

Since the ratio of money in the bags was 4:3:2, there is some constant k such that the amount in bag A is 4k, the amount in B is 3k, and the amount in C is 2k.

Adding 50 to each bag we get the following equivalent ratios (a proportion):

4k+50:3k+50:2k+50=14:13:12

Then `(4k+50)/(2k+50)=14/12` (choose a corresponding pair of ratios to set equal):

`(2k+25)/(k+25)=7/6`

`12k+150=7k+175`

`5k=25`

`k=5`

------------------------------------------------------------------

The original amounts in bags A,B, and C were $20,$15, $10.

-----------------------------------------------------------------

Check: 20:15:10= 4:3:2

70:65:60=14:13:12 as required.

## We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

- 30,000+ book summaries
- 20% study tools discount
- Ad-free content
- PDF downloads
- 300,000+ answers
- 5-star customer support

Already a member? Log in here.

Are you a teacher? Sign up now