Solve the equations: 2y-5x+3 = 0   and   3y+x -5 = 0

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted on

The set of equations to be solved are 2y-5x+3 = 0 and 3y+x -5 = 0

3y + x - 5 = 0

=> x = 5 - 3y

Substitute this in 2y - 5x + 3 = 0

=> 2y - 5(5 - 3y) + 3 = 0

=> 2y - 25 + 15y + 3 = 0

=> 17y = 22

=> y = 22/17

x = 5 - 3*(22/17)

=> (85 - 66)/17

=> 19/17

The solution of the set of equations is x = 19/17 and y = 22/17

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hala718 | High School Teacher | (Level 1) Educator Emeritus

Posted on

2y - 5x + 3 = 0..........(1)

3y + x - 5 = 0 .............(2)

We will solve the system using the elimination method.

We will multiply equation (2) by 5.

==> 15y + 5x - 25 = 0

Now we will add to (1).

==> 17y - 22 = 0

==> 17y= 22

==> y= 22/17

Now we will substitute into (2) to fin x.

==> x = 5- 3y= 5- 3(22/17) = (85-66)/17 = 19/17

Then the solution to the equations is the pair ( 19/17 , 22/17).

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