giorgiana1976 | Student

This is an elementary trigonometric equation and we'll use the following pattern to solve it:

sin x = a

x = ` ``(-1)^(k)` arcsin a + `pi` *k

Let a = 1/5

Since 1/5 < 1, therefore there are values of x for the sine function to be possible.

sin x = 1/5

x = `(-1)^(k)` arcsin (1/5) + `pi` *k

x = `(-1)^(k)` *11.53 + `pi` *k

The solutions of the equation belong to the set {`(-1)^(k)`11.53 + `pi` *k/ k`in`Z }.

Access hundreds of thousands of answers with a free trial.

Start Free Trial
Ask a Question