Solve the equation. ` log x + log sqrt x + log 2 = 1/4`

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`log x + log sqrt x + log 2 = 1/4`

Since the base of the logarithm is not indicated, it indicates that its base is 10.

`log_10x + log_10 sqrtx + log_10 2 = 1/4`

Also, since the logarithms have the same base, express them with one logarithm only. So, apply the product rule `log_b M + log_b N = log_b(MN)` .

`log_10 (x*sqrtx*2) = 1/4`

`log_10(2xsqrtx) = 14`

To simplify, express the square root in exponent form.


To multiply x and x^(1/2), apply the exponent rule `a^m*a^n=a^(m+n)` .


Then, convert the equation to its exponential form. Take note that the exponential equivalent of `log_b M=a` is `M=b^a` .


Then, isolate x.





To simplify the right side, apply the exponent rules `(a/b)^m=a^m/b^m` and `(a^m)^n=a^(m*n)` .




Hence, the solution to the given equation is `x=0.0925` . 

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