solve the equation: f(x) = x^2 - 3x + 4

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f(x) = x^2 - 3x + 4

Let us use the fomula to solve:

we note that :

delta = b^2 - 4ac = -7 is negative.

If delta < 0  , then the roots are complex ( not real).

Then we have complex roots.

x= [-b + sqrt(b^2 -...

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f(x) = x^2 - 3x + 4

Let us use the fomula to solve:

we note that :

delta = b^2 - 4ac = -7 is negative.

If delta < 0  , then the roots are complex ( not real).

Then we have complex roots.

x= [-b + sqrt(b^2 - 4ac)]/2a

x1= [3 + sqrt(9 - 16)/2 = (3+ sqrt(-7) /2 = [3 + (sqrt7)i]/2

x2= (3- (sqrt7)*i]/2

Then , the solution is:

 x= { 3/2 + (sqrt7/2)*i  ,  3/2 - (sqrt7/2)*i }

 

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