Solve the equation 5cos^2x-6tanx*cosx=cos^2x-5sin^2x-1.
- print Print
- list Cite
Expert Answers
justaguide
| Certified Educator
calendarEducator since 2010
write12,544 answers
starTop subjects are Math, Science, and Business
We have to solve 5(cos x)^2 - 6 tan x*cos x = (cos x)^2- 5*( sin x)^2 - 1
5(cos x)^2 - 6 tan x*cos x = (cos x)^2- 5*( sin x)^2 - 1
=> 5(cos x)^2 + 5*( sin x)^2 - 6 tan x*cos x = (cos x)^2 -...
(The entire section contains 267 words.)
Unlock This Answer Now
Start your 48-hour free trial to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.
Related Questions
- Prove the following identity: cos x + cos 2x + cos 3x = cos 2x(1 + 2cos x)
- 1 Educator Answer
- What is x if cos^2(x/2)-2cos^2x=(3/2)*square root2(1+cosx)+2sin^2x?
- 1 Educator Answer
- Prove the identity cotx*sinx=cosx/(cos^2x+sin^2x)
- 1 Educator Answer
- Solve the equation tan^2x=8-8secx.
- 1 Educator Answer
- What is the angle x if the identity sin2x-(cos 2x)/2 -1/2=cosx-2cosx*tanx?
- 1 Educator Answer
giorgiana1976 | Student
check Approved by eNotes Editorial
Student Answers