We have to solve 5^(2x+1)=5^-x^2
5^(2x+1)=5^-x^2
As the base is the same we can equate the exponent:
2x + 1 = -x^2
=> x^2 + 2x + 1 = 0
=> (x + 1)^2 = 0
=> x = -1
The required solution is x = -1
algebra1
We have to solve 5^(2x+1)=5^-x^2
5^(2x+1)=5^-x^2
As the base is the same we can equate the exponent:
2x + 1 = -x^2
=> x^2 + 2x + 1 = 0
=> (x + 1)^2 = 0
=> x = -1
The required solution is x = -1