Solve the equation: (3x-1)+{1/(3x-1)}=5

neela | Student


Mutiply by the denominator (3x-1) to get rid of the fractional form.


9x^2-6x +2=15x-5.


9x^2-21x+7 is a quadratic equation of the form ax^2+bx+c=0 whose roots are given by


a=9,b=-21 and c=7. Substing in the quadratic equation we get the roots:

x= [-(-21) +or- sqrt(21^2-4*9*7)}/(2*9}

x=[7+sqrt21]6   or  x=[7-sqrt21]/6

x=1.9304approximately,  or  x=0.4029 approx.

You can put back int he original equations


kmieciakp | Student


(3x-1)(3x-1) + 1 = 5(3x-1)

9x^2 -6x + 1 +1=15x-5

9x^2 -21x +2 = - 5

9x^2 -21x +7 = 0

(       )(       )=0

check the equation--it doesn't factor--see if you wrote it down right please-- I think you meant = negative 5--then it would work fine

then send it back to me . . .I love doing these things


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