We have to solve the equation 2cos(3x) -1 for values in the interval 0=< x =< pi.
Now we see that 2cos(3x) -1 is not an equation, let's equate it to zero.
2cos(3x) -1 = 0
=> 2 cos 3x -1 = 0
=> 2 cos 3x = 1
=> cos 3x = 1/2
in the given t=interval we see that cos 60= 1/2
=> cos 3x = cos 60
=> 3x = 60
=> x = 20 degrees.
Therefore the required result is x = 20 degrees.
Given the equation 2cos(3x) -1 = 0
We need to solve for x if 0=< x =< pi.
==> 2cos(3x) -1 = 0
We will add 1 to both sides.
==> 2cos(3x) = 1
Now we will divide by 2.
==> cos(3x) = 1/2
Then we know that:
3x = pi/3
Now we will divide by 3.
==> x = pi/9
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