We have to solve: e^2x - 6e^x + 5 = 0
e^2x - 6e^x + 5 = 0
let e^x = t
=> t^2 - 6t + 5 = 0
=> t^2 - 5t - t + 5 = 0
=> t(t - 5) - 1( t - 5) = 0
=> (t - 1)(t - 5) = 0
=> e^x = 1 and e^x = 5
=> x = 0 and x = ln 5
The solution of the equation is x = 0 and x = ln 5
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