Solve the equation : 2*sin^2 x + cos x - 1 = 0

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The equation `2*sin^2 x + cos x - 1 = 0` has to be solved for x.

This trigonometric equation has both sin x as well as cos x. It is possible to write `sin^2x = 1 - cos^2x` . This eliminates sin x and would allow the equation to be written as a quadratic in terms of cos x.

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user4133556 | Student

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tonys538 | Student

To solve the equation `2*sin^2 x + cos x - 1 = 0` first change `sin^2x` to `cos^2x ` so that the equation can be written in the form of a quadratic equation.

`2*sin^2 x + cos x - 1 = 0`

Use the formula `sin^2x = 1 - cos^2 x` , this gives:

`2*(1 - cos^2x) + cos x - 1 = 0`

`2 - 2*cos^2x + cos x - 1 = 0`

`-2*cos^2x + cos x + 1 = 0`

If `y = cos^2x` , the given equation is `-2y^2 + y + 1 = 0`

The solution of this quadratic equation is `(-1+-sqrt(1 + 8))/(-4)`

= `(-1+- 3)/(-4)`

= `-1/2` and 1

cos x = 1/2 gives x = 120 + n*360, x = 240 + n*360

cos x = 1 gives x = n*360

The solution of the equation is 120+n*360, 240+n*360 and n*360

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