Since the information provided by the problem is incomplete because the inequality 8x - 3> does not specify what is to the right side.

Considering as a second inequality `8x - 3 > 5` yields:

`5 - x >= 7 or 8x - 3 > 5`

You need to solve each inequality separately, such that:

`5 - x >= 7 => -x >= 7 - 5 => -x >= 2`

You need to multiply by `-1` switching the direction of inequality, such that:

`x <= -2 => x in (-oo,-2]`

Solving the second inequality yields:

`8x - 3 > 5 => 8x > 3 + 5 => 8x > 8 => x > 1`

`x in (1,oo)`

You should remember that the solution to the "or" compounded inequality is the reunion of intervals `x in (-oo,-2] U (1,oo).`

**Hence, evaluating the interval solution to the given compounded inequality yields **`x in (-oo,-2] U (1,oo).`

It is given that `5-x>=7` or `8x-3> 29`

`5-x>=7` or `8x-3> 29`

=> `5 - 7 >= x` or `8x > 32`

=> `-2 >= x` or `x > 4`

**The set that satisfies these inequalities is **`(4, oo)U[-2, -oo)`