solve by factoring 4x^2-8x+4=0 must show work

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4x^2-8x+4=0 by factoring

Factor out the GCF of 4 from each term in the polynomial.

4(x^2) + 4(-2x) + 4(1) =0

4 (x^2-2x+1)=0

4 (x-1) (x-1) =0

Combine the two common factors of (x-1) by adding the exponents.

4 (x-1)^2 =0

Divide both sides of the equation by 4 which leaves

(x-1)^2 = 0

Set each factor equal to 0

x-1 = 0

Add 1 to each side to solve for x

x=1

 

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