Solve the system using the elimination method: 3x+4y=26 x-2y=-8

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Given the equation:

3x+4y = 26...........(1)

x - 2y = -8 ............(2)

First we will multiply (2) by 2 :

==> 2x - 4y = -16...........(3)

Now we will add (1) and (3)

==> 5x = 10

==> x = 2

==> Now we will substitute x=2 into (2) to...

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Given the equation:

3x+4y = 26...........(1)

x - 2y = -8 ............(2)

First we will multiply (2) by 2 :

==> 2x - 4y = -16...........(3)

Now we will add (1) and (3)

==> 5x = 10

==> x = 2

==> Now we will substitute x=2 into (2) to find y.

==> x - 2y = -8

==> 2 - 2y = -8

==> -2y = -10

==> y= 5

Then, the solution to the system is the pair ( 2, 5)

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