# Solve by any algebraic method.   A) 4x+3y= -2  -5x-2y=9 If there is no solution to this system of equations,state the reason.          B) 2/3x+y=1   3 /4x+1/2y=3/4

Expert Answers
durbanville | Certified Educator

Please note to only post one question at a time in terms of eNotes rules. Please post your other question separately or follow the steps applied for this one:

1. `4x+3y = -2`  and  2.   `-5x - 2y = 9`

We must eliminate one of the variables (x and y) to enable us to solve this system of equations. We must first make one of the variables in each equation equal to the other. Remember with equations you can make any necessary changes as long as you change everything. So we will multiply 1. x 2 and 2. x 3 to create equation 3. and 4. -   so that we can eliminate y:

3. `2(4x) +2(3y) = 2(-2)`      and

4. `3(-5x)-3(2y) = 3(9)`

3. `therefore 8x + 6y = -4`  and 4. `-15x - 6y = 27`

Eliminate y by adding the two equations together (3.+ 4.)

`8x + (-15x) +6y + (-6y) = -4 +27`

`-7x +0y = 23`

`therefore -7x= 23`

`therefore x= 23/-7`

Now substitute into any one of the previous equations to find y:

`4x + 3y = -2`

`therefore 4(23/-7) +3y = -2`

`therefore -92/7 +3y = -2`

`therefore 3y = -2+ 13 1/7`

`therefore 3y =78/7`

`therefore y = (78/7)/3`

`therefore y = 78/7 times 1/3`  (equivalent to the previous 78/7/3)

`therefore y = 78/21`

` therefore y = 26/7or 3 5/7`

`( - 23/7; 26/7)`

The solution to the system of equations is x= -23/7 and y = 26/7

Further Reading:
oldnick | Student

`a)`

`4x+3y = -2`

`-5x-2y =9```

`4x+3y-5x-2y= -2 +9`

`y-x = 7`

`4y-4x= 28`

`4x+3y+4y-4x=-2+28`

`7y= 26`

`y=26/7`

`x=y-7=26/7 -7 =(26-49)/7=-23/7`

``

`b)`

``

`2/3 x +y = 1`

`3/4 x + 1/2 y = 3/4`

making ratio out:

`2x+3y=3`

`3x+2y=3`

subtracting second relation from first:

`2x+3y-(3x+2y)= 3 -3`

so:

`2x+3y -3x-2y = 0`

`y - x = 0`  `x= y`

subistuing in the second relation we have now:

`5x= 3`

the solutions are:    `x= y = 3/5`

oldnick | Student

`2/3 x+ y= 1`

### Access hundreds of thousands of answers with a free trial.

Ask a Question
Related Questions
Popular Questions