# solve 5x^4+50x^2+80=0

### 2 Answers | Add Yours

`5x^4+50x^2+80 = 0`

First we will factor 5 from all sides.

`==gt 5(x^4+10x +16) = 0`

`` Now we will factor the quartic equation.

`==gt 5(x^2 +8)(x^2+2) = 0`

`` Now we will find the roots.

`==gt x^2 + 8 = 0==gt x^2 = -8 `

`==gt x^2 + 2 = 0 ==gt x^2 = -2`

`` **Then, the equation has NO REAL solutions**.

However, we can find the complex roots :

`==gt x = 2sqrt2*i , -2sqrt2*i , sqrt2*i, and -sqrt2*i`

First Line: 5(x^2+8)(x^2+2)=0

Second Line: x=sqrt of -8 and sqrt of -2

Therefore there are no solutions, as you can't sqrt a negative number.