2 Answers | Add Yours
`5x^4+50x^2+80 = 0`
First we will factor 5 from all sides.
`==gt 5(x^4+10x +16) = 0`
`` Now we will factor the quartic equation.
`==gt 5(x^2 +8)(x^2+2) = 0`
`` Now we will find the roots.
`==gt x^2 + 8 = 0==gt x^2 = -8 `
`==gt x^2 + 2 = 0 ==gt x^2 = -2`
`` Then, the equation has NO REAL solutions.
However, we can find the complex roots :
`==gt x = 2sqrt2*i , -2sqrt2*i , sqrt2*i, and -sqrt2*i`
First Line: 5(x^2+8)(x^2+2)=0
Second Line: x=sqrt of -8 and sqrt of -2
Therefore there are no solutions, as you can't sqrt a negative number.
We’ve answered 318,909 questions. We can answer yours, too.Ask a question