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To solve this inequality you must first isolate the variable. To do this you must add +4 to each side. After this is done you will be left with -5v<-25. The next step will be to divide each side by -5. -5/-5v < -25/-5. Following this step you will have your answer. V< 5.
Thus, negative 4 plus a negative 5V is any number less than a negative 25. Your solution is V is any number less than 5.
-4 - 5v < -29
First you can imaging " < " as an " = " sign
So you should add 4 on both sides
By adding on both sides, you should get
-5v < -25 now divide both sides by -5
By dividing, your equation should look like
v > 5 which is your answer
now remember that for equation that has signs " > " or " < " if you divide or multiply, then you have to switch the sign
okay so you want to try to isolate the v, or the unkown variable by itself in order to do this you would add 4 to both sides (remember what you do to one side of the equal sign or > or< sign, you must do to the other
then divide by -5, but when you have > or< signs, when you divide by a negitive number, you must flip the sign
so it would be v>5.
-4-5v<-29 you first cancelled the -4 by adding +4 then you do the same to the other side by adding 4 to -29 = -25
-5v<-25 Then you divide by -5 to both sides by you need to change the symbol because you are dividing a negative
But when you multiply both sides of an inequality by a negative number, you reverse the inequality. So the answer is v>5
Note this example, if answer were v < 5 :
then -4 -(5x1)<-29
-4 - 5 < -29
-9 < -29--which is not true.
But suppose v is a number greater than 5, like 6:
-4 - (5x6) < -29
-4 - (30) < -29
-34 < -29.
and just to be sure, let's make sure v cannot equal 5:
-4 - (5-5) < -29
-4 - (0) < -29
-4 < -29--not true, so that's settled.
To recap then, solve -4 - 5v < -29 like this:
-4 - (5v) < -29
-5v < -29 +4
-5v < -25
(-1/5)5v < -25(-1/5)
when multiplying both sides of an inequality by a negative number, you need to flip the inequality
v > 5
-5v < -29 + 4
-5v < -25
v > -25/5 (Sign change so flip the inequality sign!)
v > -5
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