Solutions for logarithmic equation lnx+ln(x+1)=ln2

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We know that lnx +lny = lnxy

==> lnx+ln(x+1) =ln2

==> lnx(x+1) = ln2

==> x(x+1)=2

==> x^2+x-2=0

==> (x+2)(x-1)=0

==> x=1

      ( We will not consider x=-2 as a solution, because the function is not defined for negative values.)

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