The solution of the system x^3+y^3+x+y=32 and x^3-y^3+x-y=28 is also the solution of the equation: a. x^3+x=20 b. x^3+x=25 c. x^3+x=30

Expert Answers

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It would be easier to get the answer here by starting with the choices given.

Let us substitute the choices in the two equations: x^3+y^3+x+y=32 and x^3-y^3+x-y=28

  • x^3 + x = 20

We have y^3 + y = 32 - 20 = 12

and -y^3 - y = 28 - 20 = 8

  • x^3 + x = 25

We have y^3 + y = 32 - 25 = 7

and -y^3 - y = 28 - 25 = 3

  • x^3 + x = 30

y^3 + y = 32 - 30 = 2 ,

and -y^3 - y = 28 - 30 = -2 or y^3 + y = 2

Therefore the correct option is c. x^3+x=30.

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