A solution is prepared that is 23.44 wt% NaCl in water. What is the molality of the solution? explain the answer to me
Molality is the ratio between amount of substance of solute in moles and amount of solvent in kg.
Molality (M) = (moles of solute)/(mass of solvent)
Here the solute is NaCl and solvent is water.
23.44% wt means we have 23.44g of NaCl in 100ml of water.
For 1000ml of water we have `23.44xx10 = 234.4` g of NaCl.
Molic weight of NaCl = 58.44g/mol
moles of NaCl `= 234.4/58.44 = 4.01` moles
So we have 4.01 moles of NaCl in 1000ml of water.
Usually 1ml of water has a weight of 1g.
So in the solution we have 1000g = 1kg of water.
Molality = 4.01/1 = 4.01mol/kg
The molality of the NaCl solution is 4.01mol/kg