A solution of 1 M glucose has to be prepared. How many grams of glucose are needed for this
Molarity is a way of expressing the concentration of solute in a solution. It is the number of moles of solute in one liter of a solution.
Glucose has a chemical formula C6H12O6 and its molar mass is 180.16 g/mole.
A solution of glucose with molarity 1 M has one mole of glucose in every liter of solution. If one liter of 1 M solution of glucose has to be prepared, one mole of glucose is required. One mole of glucose is equivalent to 180.16 g of glucose.
To prepare one liter of 1 M solution of glucose 180.16 grams of glucose is required.
`"M" = ("moles")/("liters")`
You have not specified how much of the 1M glucose solution you need.
If you need 0.5 L of solution, you would need 0.5 moles of glucose, 1 L for 1 mole and so on.
To convert moles to grams, you must use dimensional analysis:
`? "moles" = (180.16"g")/(1"moles") = ? "g"`
For example, 0.5 moles of glucose would be 90.08 grams of glucose.