# A solid cube of silver (density = 10.5 g/cm3) has a mass of 90.0 g. What is the resistance between opposite faces of the cube? The solid cube of silver, between the opposite faces of which we have to find the resistance, has a density of 10.5 g/cm^3 and a mass of 90 g.

Now density is given by mass/ volume or volume is equal to mass/ density.

Here, the volume is equal to 90/...

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The solid cube of silver, between the opposite faces of which we have to find the resistance, has a density of 10.5 g/cm^3 and a mass of 90 g.

Now density is given by mass/ volume or volume is equal to mass/ density.

Here, the volume is equal to 90/ 10.5 cm^3.

The volume of a cube with sides of length l is equal to l^3

=> l^3 = 90/ 10.5

=> l = (90/10.5) ^ (1/3) cm

=> l = 2.04 cm

=> l = .0204 m

The resistivity of silver is 15.87* 10^-9 ohm*m.

So the resistance between opposite faces of the cube is: 0.0204*15.87*10^-9

=0.317*10^-9 ohm.

The required resistance between the opposite faces of the silver cube is 0.317*10^-9 ohm.

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