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To find the slope of the given line `-3x+4y=-48` , rearrange and write the equation of the straight line in slope-intercept form i.e. `y=mx+b` where `m` is the slope of the line. So,
Dividing both sides by 4 we get:
Comparing with the slope intercept form of the straight line, the slope of the given line,`m=3/4=0.75`
Therefore, the slope of the line `-3x+4y=-48` is `3/4` or 0.75.
-3x + 4y = -48
4y = 3x - 48
y = 3x/4 -12
therefore, the slope is 3/4
The slope intercept form of the equation of any line is y = mx + c where m is the slope and c is the y-intercept.
To determine the slope of -3x+4y=-48, it needs to be rewritten in the slope-intercept form.
4y = -48 + 3x
y = (3x)/4 - 48/4
y = (3/4)*x - 12
The slope of this line is 3/4
To get the slope you have to change your equation to the standard equation of a line: y=mx+b.
Your slope would be m, or the coefficient in front of x. This makes the slope 3/4.
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