To find the slope of the given line `-3x+4y=-48` , rearrange and write the equation of the straight line in slope-intercept form i.e. `y=mx+b` where `m` is the slope of the line. So,

`-3x+4y=-48`

`rArr 4y=3x-48`

Dividing both sides by 4 we get:

`y=3/4x-12`

Comparing with the slope intercept form of the straight line, the slope of the given line,`m=3/4=0.75`

**Therefore, the slope of the line `-3x+4y=-48` is `3/4` or 0.75.**

The slope intercept form of the equation of any line is y = mx + c where m is the slope and c is the y-intercept.

To determine the slope of -3x+4y=-48, it needs to be rewritten in the slope-intercept form.

-3x+4y=-48

4y = -48 + 3x

y = (3x)/4 - 48/4

y = (3/4)*x - 12

The slope of this line is 3/4

To get the slope you have to change your equation to the standard equation of a line: y=mx+b.

-3x+4y=-48

-3x=-48-4y

-3x+48=-4y

(-3x/-4)+(48/-4)=y

y=3/4x-12

Your slope would be m, or the coefficient in front of x. This makes the slope 3/4.