A skier starting from resting skis straight down a slope of 75 m long in 15 seconds. What is the magnitude of the acceleration of the skier? 

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gsenviro | College Teacher | (Level 1) Educator Emeritus

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Using the equation of motion relating distance traveled (s) to initial velocity (u), time (t) and acceleration (a):

s = ut + 1/2 at^2

Here, initial velocity = 0, since the skier was at rest, distance traveled is 75 m and time taken is 15 seconds,

s = 0 + 1/2 a t^2

Or, a = 2s/t^2 = 2 x 75/15^2 = 0.67 m/s^2.

Thus, the skier is accelerating at the rate of 0.67 m/s^2.

Hope this helps.

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