A skier starting from resting skis straight down a slope of 75 m long in 15 seconds. What is the magnitude of the acceleration of the skier?
Using the equation of motion relating distance traveled (s) to initial velocity (u), time (t) and acceleration (a):
s = ut + 1/2 at^2
Here, initial velocity = 0, since the skier was at rest, distance traveled is 75 m and time taken is 15 seconds,
s = 0 + 1/2 a t^2
Or, a = 2s/t^2 = 2 x 75/15^2 = 0.67 m/s^2.
Thus, the skier is accelerating at the rate of 0.67 m/s^2.
Hope this helps.