if sinx = 3/5 calculate cosx , tan, x and secx
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sinx = 3/5
We know that:
sin^2 x + cos^2 x = 1
==> cosx = sqrt(1-sin^2 x)
= sqrt(1- 9/25)
= sqrt( 16/25)
= 4/5
==> cosx = 4/5
Now we know that:
tanx = sinx/cosx = (3/5) / (4/5) = 3/4
==> tanx = 3/4
secx = 1/cosx = 1/(4/5) = 5/4
==> secx = 5/4
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We know that (sin x )^2 + (cos x)^2 =1
Now sin x = 3/5
=> cos x = sqrt [ 1 - (sin x)^2]
=> cos x = sqrt [ 1 - (3/5)^2]
=> cos x = sqrt [ 1 - (9/25)]
=> cos x = sqrt ( 16 /25)
=> cos x = 4/5
tan x = sin x / cos x = (3/5) / (4/5) = 3/4
sec x = 1/ tan x = 4/3
Given sinx = 3/5.
cosx = sqrt(1-sin^2x) = sqrt(1-(3/5)^2) = 4/5.in tst quadrant or -4/5 in 2nd qudrant.
secx = 1/cosx = 5/4 in 1st and -5/4 in 2nd quadrant.
tanx = sinx/cosx = (3/5)/(4/5) = 3/4 in 1st and -3/4 in 2nd quadrant.
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