Differentiate $\displaystyle y = \ln \tan ^2 x $
$ \begin{equation} \begin{aligned} \text{if } y =& \ln \tan ^2 x, \text{ then } \\ \\ y' =& \frac{\displaystyle \frac{d}{dx} (\tan^2 x) }{\tan^2 x} \\ \\ y' =& \frac{2 (\tan x)(\sec^2 x)}{\tan ^2 x} \\ \\ y' =& \frac{2 \sec^2 x}{\tan x} \\ \\ y' =& \frac{\displaystyle 2 \left( \frac{1}{\cos ^ 2x} \right)}{\displaystyle \frac{\sin x}{\cos x}} \end{aligned} \end{equation} $
Posted on
We’ll help your grades soar
Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.
- 30,000+ book summaries
- 20% study tools discount
- Ad-free content
- PDF downloads
- 300,000+ answers
- 5-star customer support
Already a member? Log in here.
Are you a teacher? Sign up now