Find the value generated by rotating $\mathscr{R}_2$ about $OC$

If you rotate $\mathscr{R}_2$ about $OC$, by using horizontal strip, you will form a disk with radius $y^2$. Thus, the cross sectional area can be computed as $A(y) = \pi(y^2)^2$. Therefore, the value is...

$ \begin{equation} \begin{aligned} V &= \int^1_0 \pi y^4 dy\\ \\ V &= \pi \left[ \frac{y^5}{5} \right]^1_0\\ \\ V &= \frac{\pi}{5} \text{ cubic units} \end{aligned} \end{equation} $

## We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

- 30,000+ book summaries
- 20% study tools discount
- Ad-free content
- PDF downloads
- 300,000+ answers
- 5-star customer support

Already a member? Log in here.

Are you a teacher? Sign up now