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(sinB)-3sinB+2=0 where 0 less or equal to B less or equal to 2 pie? solve the equation.

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We have to solve (sin B)-3sin B+2=0 for B in the range [0, 2*pi]

(sin...

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giorgiana1976 | Student

We'll combine like terms in sin B:

-2sinB + 2 = 0

We'll factorize by 2:

2(-sin B + 1) = 0

We'll divide by 2:

-sin B + 1 = 0

We'll subtract 1:

-sin B = -1

sin B = 1

B = pi/2 since this is the only value in the interval [0 ; 2pi], for sin B = 1.

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