(sinB)-3sinB+2=0 where 0 less or equal to B less or equal to 2 pie? solve the equation.
We have to solve (sin B)-3sin B+2=0 for B in the range [0, 2*pi]
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We'll combine like terms in sin B:
-2sinB + 2 = 0
We'll factorize by 2:
2(-sin B + 1) = 0
We'll divide by 2:
-sin B + 1 = 0
We'll subtract 1:
-sin B = -1
sin B = 1
B = pi/2 since this is the only value in the interval [0 ; 2pi], for sin B = 1.