If sin x = -3/5 and pi <= x <=3pi/2, find cos x and tan x. I have the correct answers from the book (-4/5 and 3/4 respectively) but don't know how to work out the question. Thanks!

Expert Answers

An illustration of the letter 'A' in a speech bubbles

You should know that the values of sin and cos in the third quadrant are negative, hence the values of tan and cot are positive.

You need to use the basic trigonometric formula such that:

`sin^2x + cos^2x = 1 =gt cos x = - sqrt(1 - sin ^2x)`

Plugging...

See
This Answer Now

Start your subscription to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.

Start your Subscription

You should know that the values of sin and cos in the third quadrant are negative, hence the values of tan and cot are positive.

You need to use the basic trigonometric formula such that:

`sin^2x + cos^2x = 1 =gt cos x = - sqrt(1 - sin ^2x)`

Plugging sin x =`-3/5`  in the formula above yields:

`cos x = - sqrt(1 - (-3/5)^2) =gt cos x = -sqrt(16/25) =gt cos x = -4/5`

You should use the following formula to find tan x:

`1 + tan^2 x = 1/cos^2 x =gt tan^2 x = 1/cos^2 x - 1`

`tan^2 x = 1/(16/25) - 1 =gt tan^2 x = 25/16 - 1`  =>`tan^2 x = 9/16`

Since the value of tan x is positive in the third quadrant =>

tan x = `sqrt(9/16)`  => tan x = `3/4`

Hence the requested values for cos x and tan x are: cos x = -`4/5`  and tan x = `3/4` .

Approved by eNotes Editorial Team
An illustration of the letter 'A' in a speech bubbles

The answer is very easy. According to the question, x lies in the third quarter. In the third quarter, only tan is positive, sin and cos values are negative. You can use the general formula,

sin^2(x)+cos^2(x) = 1

this gives, (-3/5)^2 + cos^2(x) = 1

therefore, cos^2(x) = 1 - 9/25 = 16/25

taking the squareroot, cos(x) = +/- sqrt(16/25) = +/- (4/5)

since x is in the third quarter, cos(x) is negative and equals to -(4/5).

tan(x) = sin(x)/cos(x) = (-3/5) / (-4/5) = 3/4

 

Hope it is clear for you.

Approved by eNotes Editorial Team