`(sin(pix) + cos(piy))^2 = 2` Find `dy/dx` by implicit differentiation.

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hkj1385 | (Level 1) Assistant Educator

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`[sin(pix) + cos(piy)]^2 = 2`

Differentiating both sides w.r.t 'x' we get

`2[sin(pix) + cos(piy)]*[pi*cos(pix) - pi*sin(piy)*(dy/dx)] = 0`

`or, [pi*cos(pix) - pi*sin(piy)*(dy/dx)] = o`

`or, dy/dx = cos(pix)/sin(piy)`

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