`sin(arctan(x))` Write an algebraic expression that is equivalent to the given expression. (Hint: Sketch a right triangle.)

kspcr111 | Student

`sin(arctan(x))`

let `theta = arctan(x)`

=> `tan(theta)=x= x/1`

by using the right triangle we get the hypotenuse is `= sqrt(1+x^2)`

so `sin(theta) = x/(sqrt(1+x^2))`