`sin(-(8pi)/3)` Evalute the trigonometric function using its period as an aid

kspcr111 | Student

Given

`sin(-8pi/3)`

= `-sin(8pi/3)`

= `-sin(2pi +2pi/3)`

= `-sin(2pi/3)`

= `-sin(pi - pi/3)`

= `-sin(pi/3)`

= `-sqrt(3)/2`