Simplify: `root(4)(32x^11y^15)` divided by `root(4)(2x^3y^2)`
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The expression `(root(4)(32x^11*y^15))/(root(4)(2x^3y^2))` has to be simplified.
`(root(4)(32x^11*y^15))/(root(4)(2x^3y^2))`
= `(32x^11*y^15)^(1/4)/(2x^3y^2)^(1/4)`
= `((32x^11*y^15)/(2x^3y^2))^(1/4)`
= `(32/2)^(1/4)*x^((11-3)/4)*y^((15 - 2)/4)`
= `16^(1/4)*x^(8/4)*y^(13/4)`
= `2*x^2*y^(13/4)`
The simplified form of `(root(4)(32x^11*y^15))/(root(4)(2x^3y^2)) = 2*x^2*y^(13/4)`
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Since both the numerator and the denominator are to the fourth root, another way to write the equation is:
`root(4)((32x^11y^15)/(2x^3y^2))`
We can simplify inside the root by dividing like terms:
`root(4)(16x^8y^13)`
Then take the fourth root (if possible!) of each part under the root (16, x, and y):
`root(4)16 = 2`
`root(4)(x^8) = x^2`
`root(4)(y^13) = y^3(root(4)y)`
Put them together can you get:
`2x^2y^3root(4)y`
` `
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