trigonometry math

Start Free Trial

Simplify the fraction [cosx*sin(2x)-2sinx]/sin^2 x*cosx=?

Expert Answers

An illustration of the letter 'A' in a speech bubbles

We have to simplify: [cos x*sin(2x) - 2 sin x]/(sin x)^2 *cos x

[cos x*sin(2x) - 2 sin x]/(sin x)^2 *cos x

use sin 2x = 2*sin x * cos x

=> [2*(cos x)^2 *sin x - 2 sin x]/(sin x)^2 *cos x

=> [2*(cos x)^2 - 2]/sin x *cos x

=> [2*(cos x)^2/ sin x*cos x] - [2/sin x *cos x]

=> [2*cos x/ sin x] - [4/ 2*sin x*cos x]

=> [2*cos x/ sin x] - [4/ sin 2x]

=> 2*cot x - 4*cosec 2x

The required result is 2*cot x - 4*cosec 2x

Approved by eNotes Editorial Team