Simplify the expression [(x^2-6x+5)/(x+3)]*[(x^2-9)/(x-5).

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Let E = (x^2-6x+5) / (x+3) * (x^2-9)/(x-5)

First we will multiply numerators and denominators:

==> E = (x^2-6x+5)*(x^2-9)/(x+3)(x-5)

Now we will factor the numerator:

==> E = (x-5)(x-1)(x-3)(x+3)/(x+3)(x-5)

Now we will reduce similar terms.

==> E = (x-1)(x-3)

==> E = (x-1)(x-3) = x^2 -4x + 3

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Let E = (x^2-6x+5) / (x+3) * (x^2-9)/(x-5)

First we will multiply numerators and denominators:

==> E = (x^2-6x+5)*(x^2-9)/(x+3)(x-5)

Now we will factor the numerator:

==> E = (x-5)(x-1)(x-3)(x+3)/(x+3)(x-5)

Now we will reduce similar terms.

==> E = (x-1)(x-3)

==> E = (x-1)(x-3) = x^2 -4x + 3

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