# Simplify the expression. State the excluded values, if any. w^2+6w+9/2w^2-18

*print*Print*list*Cite

### 1 Answer

`(w^2+6w+9)/(2w^2-18)`

`=(w^2+2*3*w+3^2)/(2(w^2-3^2))`

`=(w+3)^2/(2(w-3)(w+3))`

`=(w+3)/(2(w-3))` (assuming `w!=-3` )

Again, w=3 would make the denominator equal to zero, and the expression, undefined.

Hence, excluded values of w in this expression are `+-3` .