Simplified productSimplify (8-6i)(-4-4i).
4 Answers
justaguide | College Teacher | (Level 2) Distinguished Educator
To simplify (8-6i)(-4-4i) open the brackets and multiply the terms
(8-6i)(-4-4i)
=> 8*-4 - 8*4i - 6i*(-4) - 6i*(-4i)
=> -32 - 32i + 24i + 24i^2
=> -32 - 8i - 24
=> -56 - 8i
The required product of is -56 - 8i
givingiswinning | Student, Grade 10 | (Level 1) Valedictorian
(8-6i)(-4-4i)
8x-4 - 8x4i - 6ix(-4) - 6ix(-4i)
-32 - 32i + 24i + 24i^2
-32 - 8i - 24
-56 - 8i
atyourservice | Student, Grade 11 | (Level 3) Valedictorian
(8-6i)(-4-4i)
just FOIL
multiply 8 by all the numbers in the 2nd parentheses and then do the same with -6i
-32 - 32i + 24i + 24i^2
remember i^2 = -1
-32 - 32i + 24i + 24(-i)
now simplify by combining like terms:
-32 - 8i - 24
-32 - 24 -8i
-58 - 8i
giorgiana1976 | College Teacher | (Level 3) Valedictorian
This problem requires to apply the property of distributivity of multiplication over the addition.
We'll remove the brackets:
(8-6i)(-4-4i) = 8*(-4-4i) - 6i(-4-4i)
We'll remove the brackets from the right side:
(8-6i)(-4-4i) = -32 - 32i + 24i + 24i^2
We'll use the fact that i^2 = -1.
(8-6i)(-4-4i) = -32 - 8i - 24
We'll combine real terms:
(8-6i)(-4-4i) = -56 - 8i