Simplify (3x^4)^9 / (3^5x^6)^3 using the laws of exponents, then evaluate. Thank you!
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mlehuzzah
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exponents of exponents multiply, so:
`(x^4)^9=x^(36)`
`(3^5)^3=3^(15)`
`(x^6)^3=x^(18)`
So:
`((3x^4)^9)/((3^5x^6)^3) = (3^9x^(36))/(3^(15)x^(18))`
`a^b/a^c=a^(b-c)`, so:
`(3^9)/(3^(15)) = 3^(-6)` or `1/3^6`
`(x^(36))/(x^(18))=x^(18)`
Thus:
`(3^9x^(36))/(3^(15)x^(18)) = x^(18)/3^6 = x^(18)/729`
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