# Simplify `12^2+12^2+12^2+......+12^2` Assume there are 12 of the 12^2. Please show your workings clearly.Thanks

*print*Print*list*Cite

### 2 Answers

We start with:

`12^2 + 12^2 + ... + 12^2` , where we have 12 of the `12^2.`

Since we have 12 of each, we can re-write the expression:

`12^2 + 12^2 + 12^2 + 12^2 + 12^2 + 12^2 + 12^2 + 12^2 + 12^2 + 12^2 + 12^2 + 12^2` as:

`12 times 12^2`

Note that 12 is the same as `12^1`

Hence,

`12^1 times 12^2` is `12^(1 + 2)` (since they have the same base, we can simply add the exponents. This then, simplifies to `12^3` (or 1728) .

we know 12^2 = 144.

There are 12 of the 12^2.

Multiplication is repeated addition.

Therefore, 12^2 + 12^2 + 12^2 ... + 12^2 = (12^2)(12)

which equals

12^3 = 1728