# The simplest form, in therms of i.What is simplest form, in therms of i. (i+6)(5i^2-5)

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Expert Answers

justaguide | Certified Educator

To simplify (i+6)(5i^2-5), first notice that we have i^2, this is equal to -1.

So we have (i+6)(5i^2-5)

=> (i + 6)(-5 - 5)

=> (i + 6)(-10)

Open the brackets and multiply

=> -10i - 10*6

=> -10i - 60

**The required simplified form of (i+6)(5i^2-5) is -10i - 60.**

Student Comments

giorgiana1976 | Student

We'll have to multiply the pairs of brackets and we'll apply the distributive property of multiplication, over addition.

For the beginning, we notice that the second factor contains the term i^2 = -1.

(i+6)(5i^2-5) = (i+6)(-5-5)

(i+6)(5i^2-5) = -10(i + 6)

(i+6)(5i^2-5) = -10*i - 10*6

(i+6)(5i^2-5) = -60 - 10i

**The simplest form, in terms of i, of the given expresison is:**

(i+6)(5i^2-5)** = **-60 - 10i