The simplest form, in therms of i.What is simplest form, in therms of i. (i+6)(5i^2-5)

Expert Answers
justaguide eNotes educator| Certified Educator

To simplify (i+6)(5i^2-5), first notice that we have i^2, this is equal to -1.

So we have (i+6)(5i^2-5)

=> (i + 6)(-5 - 5)

=> (i + 6)(-10)

Open the brackets and multiply

=> -10i - 10*6

=> -10i - 60

The required simplified form of (i+6)(5i^2-5) is -10i - 60.

giorgiana1976 | Student

We'll have to multiply the pairs of brackets and we'll apply the distributive property of multiplication, over addition.

For the beginning, we notice that the second factor contains the term i^2 = -1.

(i+6)(5i^2-5) = (i+6)(-5-5)

(i+6)(5i^2-5) = -10(i + 6)

(i+6)(5i^2-5) = -10*i - 10*6

(i+6)(5i^2-5) = -60 - 10i

The simplest form, in terms of i, of the given expresison is:

(i+6)(5i^2-5) = -60 - 10i

Access hundreds of thousands of answers with a free trial.

Start Free Trial
Ask a Question