The simplest form, in therms of i.What is simplest form, in therms of i. (i+6)(5i^2-5)

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justaguide's profile pic

justaguide | College Teacher | (Level 2) Distinguished Educator

Posted on

To simplify (i+6)(5i^2-5), first notice that we have i^2, this is equal to -1.

So we have (i+6)(5i^2-5)

=> (i + 6)(-5 - 5)

=> (i + 6)(-10)

Open the brackets and multiply

=> -10i - 10*6

=> -10i - 60

The required simplified form of (i+6)(5i^2-5) is -10i - 60.

giorgiana1976's profile pic

giorgiana1976 | College Teacher | (Level 3) Valedictorian

Posted on

We'll have to multiply the pairs of brackets and we'll apply the distributive property of multiplication, over addition.

For the beginning, we notice that the second factor contains the term i^2 = -1.

(i+6)(5i^2-5) = (i+6)(-5-5)

(i+6)(5i^2-5) = -10(i + 6)

(i+6)(5i^2-5) = -10*i - 10*6

(i+6)(5i^2-5) = -60 - 10i

The simplest form, in terms of i, of the given expresison is:

(i+6)(5i^2-5) = -60 - 10i

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