# show x,y intercepts of f(x)=2^x -2?

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You need to remember that the graph of function intercepts x axis at y=0, hence f(x)=y=0.

You need to solve the equation `2^x - 2= 0` .

I suggest to you to isolate the term containing x to the left side, hence:

`2^x = 2`

Since the base are alike you may equate the exponents such that:

x = 1

Hence, the graph intercepts x axis at the point (1,0).

You need to remember that the graph intercepts y axis at x = 0, hence, you need to substitute 0 for x in the equation of function such that `f(0) = 2^0- 2 = -1.`

Hence, the graph intercepts y axis at the point (0,-1).

The image below represents the graph intercepts to x axis and y axis.

**Hence, the graph intercepts x axis at the point (1,0) and it intercepts y axis at the point (0,-1).**