Show that the ratio of the sum of first n terms of a G.P to the sum of terms from (n+1)th to (2n)th term is 1/(r)n(1divided by r to the power n)..? please answer it as fast as possible...
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You need to remember how to evaluate the sum of n terms of geometric progression such that:
`S_n_1 = (a_1)*(r^n - 1)/(r-1)`
Notice that 1 represents the value of the first terms of geometric progression and r represents the common ratio.
You need to evaluate the sum of the n terms of the same...
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