Show sin 67 degrees equals to cos 23 degrees This is year 11 trigonometry. And yea I don't understand this question
sin67 = cos23
This is a true comment.
sin67 = 0.9205
cos23 = 0.9205
Usually if `alpha` is any small angle;
`sinalpha = cos(90-alpha)`
`cosalpha = sin(90-alpha)`
If `alpha = 67` then;
`90-alpha = 90-67 = 23`
Consider a triangle ABC,
In which angle A=67, angle B=90 and angle C=23 (degrees)
Then, Sin A = sin 67 = BC/CA (Since sine is ratio of : side opposite to angle divided by hypotenuse)______(1)
Also Cos C = cos 23 = BC/CA (Since cosine is ratio of : Adjacent side divided by hypotenuse)______(2)
From (1) and (2) we can say that sin 67= cos 23 (Degrees).