# Show sin 67 degrees equals to cos 23 degreesThis is year 11 trigonometry. And yea I don't understand this question

*print*Print*list*Cite

Expert Answers

Student Comments

rjtjain | Student

Consider a triangle ABC,

In which angle A=67, angle B=90 and angle C=23 (degrees)

Then, Sin A = sin 67 = BC/CA (Since sine is ratio of : side opposite to angle divided by hypotenuse)______(1)

Also Cos C = cos 23 = BC/CA (Since cosine is ratio of : Adjacent side divided by hypotenuse)______(2)

From (1) and (2) we can say that sin 67= cos 23 (Degrees).